Unusual tire wear help

[MAN OF BLUES]

.... Just looking at MOB's pics it looks like he needs to lean a little more in both directions.

heyyyyyyyyyyyyyyyyyyyy 

I Just sent you the last set I pulled off....should be at your house in a couple days...
(C.O.D. of course....)

see ya in a week...J.C. or bust..

[Scaffolder]

Interesting read.

http://www.allaboutbikes.com/motorcycle-news/general-news/2744-the-mystery-of-left-side-tire-wear-explained

[Scaffolder]

Solution.

https://www.youtube.com/watch?v=8meexuoFka4

[tweeter55]

Or, this:
http://youtu.be/iAgX6qlJEMc

[Rhino]

The average lane width is 10'. Of course this varies but that is the average of a rural 2 lane road. Highways are 12' widths. Therefor for a undivided 2 lane road I would think 5' either side of the center would be more accurate than 4'. On 4 lane divided highways I would guess 20' average difference from center. Therefor a 100' diameter curve on a 4 lane divided highway would be 80' diameter going right versus 120' going left. Still a tight curve and only about 17% difference in distance. But what is the road angle at the center of the lane due to the average crown? I can't seem to find the data but is is more then 1 or 2 degrees off at the lane center versus road center? Does that adequately explain the left side wear at 5 to 10 degrees off center? IDK. But I suspect both theories come into play.

[Rhino]

found this:



This says the slope for the crown is 1/4" per foot or 0.0208 which is about 1.2 degrees. Doesn't adequately explain the left side tire wear IMO.

[MAN OF BLUES]

The average lane width is 10'. Of course this varies but that is the average of a rural 2 lane road. Highways are 12' widths. Therefor for a undivided 2 lane road I would think 5' either side of the center would be more accurate than 4'. On 4 lane divided highways I would guess 20' average difference from center. Therefor a 100' diameter curve on a 4 lane divided highway would be 80' diameter going right versus 120' going left. Still a tight curve and only about 17% difference in distance. But what is the road angle at the center of the lane due to the average crown? I can't seem to find the data but is is more then 1 or 2 degrees off at the lane center versus road center? Does that adequately explain the left side wear at 5 to 10 degrees off center? IDK. But I suspect both theories come into play.

response #12 with my calcs was on the prior page

ex: 
90 degree turn, dt= distance travelled

25 ft center rad, right turn 21 ft r. (33' dt), left turn 29 ft r. (45.6'dt) =28% diff.
60ft center rad.,  right turn 56' r. (88'dt), left turn 64' r. (100.5'dt) = 14% diff
100 ft center rad.,  right turn 96' r. ( 150.8'dt), left turn 104' r. (163.4'dt) = 8% diff.....

[works4me]

Combine MOB's calcs with the higher speeds and the subsequently
greater lateral forces resulting from the larger radius and it's easy
to see why there is increased wear in left hand turns.

[RFH87_Connie]

Combine MOB's calcs with the higher speeds and the subsequently
greater lateral forces resulting from the larger radius and it's easy
to see why there is increased wear in left hand turns.

Totally agree.  But the original poster has worn down the RIGHT side of his tire.  Anyone?  Maybe plays on freeway ramps a lot?  I still think he does donuts to the right...

[Rhino]

response #12 with my calcs was on the prior page

ex: 
90 degree turn, dt= distance travelled

25 ft center rad, right turn 21 ft r. (33' dt), left turn 29 ft r. (45.6'dt) =28% diff.
60ft center rad.,  right turn 56' r. (88'dt), left turn 64' r. (100.5'dt) = 14% diff
100 ft center rad.,  right turn 96' r. ( 150.8'dt), left turn 104' r. (163.4'dt) = 8% diff.....

Yes, I was responding to this. Just saying 4' difference from center isn't enough IMO because 1) roads are wider and therefor 5' difference is more accurate for 2 lane and 2) divided highways are much bigger difference right turn versus left.